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The possible existence of a particle-stable ⁵H is discussed by (BL57B) who point out that a T = 3/2 level of ⁵He - ⁵Li might plausibly be formed by combination of ³H or ³He and a deuteron in the singlet (T = 1) state at an energy ~ 2.3 MeV higher than the known 16.7 - 16.8 MeV level. If such a level exists, calculation of Coulomb corrections and n - ¹H mass difference suggests a mass excess of 32.22 MeV for ⁵H, which would be 0.35 MeV stable against ³H + 2n. Presumably ⁵H would then decay by β-emission (~ 19 MeV) followed by neutron emission (BL57B). A search for delayed neutrons from ⁷Li(γ, 2p)⁵H with 320-MeV bremsstrahlung yielded no evidence of formation of ⁵H (TA58C). It is concluded that less than 1% of the expected yield of ⁷Li(γ, 2p)⁵H leads to a particle-stable product (TA58C); see also (CE58). A reaction yielding ⁵H might be ³H(t, p)⁵H with Q ~ -8.1 MeV, assuming the mass of ⁵H given by (BL57B).